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Model-independent measurement of mixing parameters in D0 → K S 0 π+π− decaysстатья
Статья опубликована в высокорейтинговом журнале
Информация о цитировании статьи получена из
Web of Science,
Scopus
Статья опубликована в журнале из списка Web of Science и/или Scopus
Дата последнего поиска статьи во внешних источниках: 26 января 2017 г.
- Авторы: LHCb c., Obraztsov V.F.
- Журнал: Journal of High Energy Physics
- Том: 2016
- Номер: 4
- Год издания: 2016
- Издательство: IOP Publishing
- Местоположение издательства: [Bristol, UK], England
- Первая страница: 033
- DOI: 10.1007/jhep04(2016)033
- Аннотация: The product of the Λ0bΛb0 (B¯¯¯¯0B¯0) differential production cross-section and the branching fraction of the decay Λ0b→J/ψpK−Λb0→J/ψpK− (B¯¯¯¯0→J/ψK¯¯¯¯¯∗(892)0B¯0→J/ψK¯∗(892)0) is measured as a function of the beauty hadron transverse momentum, pTpT, and rapidity, yy. The kinematic region of the measurements is pT<20 GeV/cpT<20 GeV/c and 2.0<y<4.52.0<y<4.5. The measurements use a data sample corresponding to an integrated luminosity of 3 fb−13 fb−1 collected by the LHCb detector in pppp collisions at centre-of-mass energies s√=7 TeVs=7 TeV in 2011 and s√=8 TeVs=8 TeV in 2012. Based on previous LHCb results of the fragmentation fraction ratio, fΛ0B/fdfΛB0/fd, the branching fraction of the decay Λ0b→J/ψpK−Λb0→J/ψpK− is measured to be B(Λ0b→J/ψpK−)=(3.17±0.04±0.07±0.34+0.45−0.28)×10−4, B(Λb0→J/ψpK−)=(3.17±0.04±0.07±0.34−0.28+0.45)×10−4, where the first uncertainty is statistical, the second is systematic, the third is due to the uncertainty on the branching fraction of the decay B¯¯¯¯0→J/ψK¯¯¯¯¯∗(892)0B¯0→J/ψK¯∗(892)0, and the fourth is due to the knowledge of fΛ0b/fdfΛb0/fd. The sum of the asymmetries in the production and decay between Λ0bΛb0 and Λ¯¯¯¯0bΛ¯b0 is also measured as a function of pTpT and yy. The previously published branching fraction of Λ0b→J/ψpπ−Λb0→J/ψpπ−, relative to that of Λ0b→J/ψpK−Λb0→J/ψpK−, is updated. The branching fractions of Λ0b→P+c(→J/ψp)K−Λb0→Pc+(→J/ψp)K− are determined.
- Добавил в систему: Образцов Владимир Федорович